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CGP EDU Academic Team
Published on: September 12, 2026
A block is lying on an inclined plane which makes $60^\circ$ with the horizontal. If coefficient of friction between block and plane is 0.25 and $g = 10 \, \mathrm{m/s^2}$ , then acceleration of the block when it moves along the plane will be
Text Solution
Verified by ExpertsThe correct answer is:
C
a $= g(\sin \theta - \mu \cos \theta) = 10(\sin 60^\circ - 0.25 \cos 60^\circ)$
a = 7.4 m/s²
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